cstr/llama3-8b-spaetzle-v39-q4_0-GGUF overview
llama3 8b spaetzle v39 llama3 8b spaetzle v39 is a merge of the following models: cstr/llama3 8b spaetzle v38 cstr/llama3 8b spaetzle v36 cstr/llama3 8b spaetz…
Runs locally from ~4.34 GB disk (8 GB VRAM class GPUs with llama.cpp / guIDE).
Repository Files & Downloads
| File | Type | Quantization | Size | Link |
|---|---|---|---|---|
| llama3-8b-spaetzle-v39.Q4_0-f32.gguf | GGUF | F32 | 4.34 GB | Download |
Model Details
Model README
---
tags:
- merge
license: llama3
language:
- de
- en
---
llama3-8b-spaetzle-v39
llama3-8b-spaetzle-v39 is a merge of the following models:
- cstr/llama3-8b-spaetzle-v38
- cstr/llama3-8b-spaetzle-v36
- cstr/llama3-8b-spaetzle-v33
- cstr/llama3-8b-spaetzle-v28
Evaluation
Quantised as q4km gguf, it achieves
on EQ Bench (v2_de): 65.12 (171 parseable),
on EQ Bench (v2): 73.64 (171 parseable).
| Model |AGIEval|GPT4All|TruthfulQA|Bigbench|Average|
|----------------------------------------------------------------------------|------:|------:|---------:|-------:|------:|
|llama3-8b-spaetzle-v39| 43.43| 73.31| 60| 45.89| 55.66|
GPT4All
| Task |Version| Metric |Value| |Stderr|
|-------------|------:|--------|----:|---|-----:|
|arc_challenge| 0|acc |60.75|± | 1.43|
| | |acc_norm|63.40|± | 1.41|
|arc_easy | 0|acc |85.10|± | 0.73|
| | |acc_norm|83.46|± | 0.76|
|boolq | 1|acc |84.74|± | 0.63|
|hellaswag | 0|acc |62.23|± | 0.48|
| | |acc_norm|80.73|± | 0.39|
|openbookqa | 0|acc |38.00|± | 2.17|
| | |acc_norm|46.80|± | 2.23|
|piqa | 0|acc |79.92|± | 0.93|
| | |acc_norm|80.25|± | 0.93|
|winogrande | 0|acc |73.80|± | 1.24|
Sample output
>>> What is 7777 + 3333?
Let's do the math:
7777 + 3333 = 11110
>>> I have 10 apples. I find 3 gold coins in the bottom of a river. The river runs near a big city that has something to
... do with what I can spend the coins on. I then lose 4 apples but gain a gold coin. Three birds run into my path and dr
... op 6 apples each. I play an online game and win 6 gold coins but I have to share them equally with my 2 teammates. I
... buy apples for all the coins I have. The price of an apple is 0.5 coins. How many apples do I have? And where is the
... river?
Let's break this down step by step!
Initially, you have 10 apples.
You find 3 gold coins in the river.
No mention of spending these coins yet.
You lose 4 apples, leaving you with 6 apples.
You gain a gold coin, so now you have 4 coins (3 + 1).
Then, three birds drop 6 apples each, which is a total of 18 apples. You now have:
6 (initial apples) + 18 (new apples) = 24 apples
In the online game, you win 6 gold coins, but since you have to share with teammates, each of you gets 2 coins (6 ÷
3). So, you gain 2 new coins.
You now have a total of 6 coins (4 initial + 2 gained).
With your 6 coins, you can buy apples at a rate of 0.5 coins per apple.
To find out how many apples you can buy, divide the number of coins by the price per apple:
6 coins ÷ 0.5 coins/apple = 12 apples
So, after buying apples with all your coins, you have a total of 24 (initial) + 12 (new) = 36 apples.
As for where the river is, it runs near a big city that has something to do with spending gold coins. Since you
bought apples with your coins, we can infer that this city might be a market or a place where fruits and goods are
sold. However, the exact location of the river is not specified in the story.
>>> Two years ago, I was three times as old as my brother was. In three years, I will be twice as old as my brother. How
... old is each of us now?
...
Let's use variables to represent the current ages:
* My current age = M
* My brother's current age = B
Two years ago, the equation would be:
M - 2 = 3(B - 2)
Since I was three times as old as my brother two years ago, we can simplify the equation:
M - 2 = 3B - 6
M = 3B - 4
Now, let's look at the future situation in three years:
M + 3 = 2(B + 3)
Expanding and simplifying:
M + 3 = 2B + 6
M = 2B + 3
We now have two equations with two variables:
1) M = 3B - 4
2) M = 2B + 3
Equating the right sides of these equations, we get:
3B - 4 = 2B + 3
Simplifying and solving for B (my brother's current age):
B = 7
Now that we know my brother's current age, we can find mine:
M = 3B - 4
= 3(7) - 4
= 21 - 4
= 17
So, I am currently 17 years old, and my brother is currently 7 years old.
🧩 Configuration
models:
- model: cstr/llama3-8b-spaetzle-v33
- model: cstr/llama3-8b-spaetzle-v38
- model: cstr/llama3-8b-spaetzle-v36
- model: cstr/llama3-8b-spaetzle-v28
merge_method: model_stock
base_model: cstr/llama3-8b-spaetzle-v33
dtype: bfloat16
💻 Usage
!pip install -qU transformers accelerate
from transformers import AutoTokenizer
import transformers
import torch
model = "cstr/llama3-8b-spaetzle-v39"
messages = [{"role": "user", "content": "What is a large language model?"}]
tokenizer = AutoTokenizer.from_pretrained(model)
prompt = tokenizer.apply_chat_template(messages, tokenize=False, add_generation_prompt=True)
pipeline = transformers.pipeline(
"text-generation",
model=model,
torch_dtype=torch.float16,
device_map="auto",
)
outputs = pipeline(prompt, max_new_tokens=256, do_sample=True, temperature=0.7, top_k=50, top_p=0.95)
print(outputs[0]["generated_text"])
Provenance and EU AI Act Art. 53 note
- Base model: cstr/llama3-8b-spaetzle-v39 — a mergekit merge published by the same maintainer as this repository. It is not a third-party upstream: the maintainer authored that model.
- What was done here: format conversion and/or quantisation of that base model only (GGUF, INT4 precision). No further training, fine-tuning or merging was applied at this step.
- Licence:
llama3, inherited through the base model from the models it was built from. - Training data: none was used, added or selected at this conversion step. The base model's card lists the models it was built from; their training content is documented — where it is documented at all — by their respective providers.
- Provider status: under Regulation (EU) 2024/1689 this repository makes no provider claim for the conversion step. Any provider obligations attaching to the model itself — including Art. 53(1)(c) copyright policy and Art. 53(1)(d) training-content summary — attach at cstr/llama3-8b-spaetzle-v39, not here.
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